Java Implementation of Problem 6
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1/*
2Project Euler Problem 6
3
4This turned out to be really easy
5
6Problem:
7
8The sum of the squares of the first ten natural numbers is,
91**2 + 2**2 + ... + 10**2 = 385
10
11The square of the sum of the first ten natural numbers is,
12(1 + 2 + ... + 10)**2 = 55**2 = 3025
13
14Hence the difference between the sum of the squares of the first ten natural
15numbers and the square of the sum is 3025 − 385 = 2640.
16
17Find the difference between the sum of the squares of the first one hundred
18natural numbers and the square of the sum.
19*/
20package euler;
21
22public class p0006 implements IEuler {
23 @Override
24 public Object answer() {
25 int sum_of_squares = 0, sum = 0;
26 for (int i = 1; i < 101; i++) {
27 sum += i;
28 sum_of_squares += i * i;
29 }
30
31 int square_of_sum = sum * sum;
32 return square_of_sum - sum_of_squares;
33 }
34}